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DAU/MAU Stickiness per Day

SQLHardSenior levelSnapchat~15 min

Problem

**[Asked at Snapchat]**

Stickiness = DAU / MAU. DAU = distinct users active that day. MAU = distinct users active in the preceding 28 days.

Return `activity_date`, `dau`, `mau`, and `stickiness` (rounded to 2 dp), ordered by date.

Tables

Example rows — the live problem includes the full dataset.

user_activity
activity_iduser_idactivity_date

Expected output

Your answer should return 3 rows with the columns activity_date, dau, mau, stickiness.

Starter code (SQL)

SELECT *
FROM user_activity;

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