Library Checkouts by Weekday and Genre

Problem

A public library tracks how many copies of each title were checked out.

Table: `Checkouts`

```text
+-------------+---------+
| Column | Type |
+-------------+---------+
| checkout_id | int |
| patron_id | int |
| taken_on | date |
| title_id | varchar |
| copies | int |
+-------------+---------+
checkout_id is the primary key. copies is the number of copies taken in that checkout.
```

Table: `Titles`

```text
+-----------+---------+
| Column | Type |
+-----------+---------+
| title_id | varchar |
| title_name| varchar |
| genre | varchar |
+-----------+---------+
title_id is the primary key.
```

For every genre, report the total number of copies checked out on each day of the week. Output one row per genre with columns `genre`, `Monday`, `Tuesday`, `Wednesday`, `Thursday`, `Friday`, `Saturday`, `Sunday`. A genre with no checkouts on a given day must show 0 for that day, and every genre in the catalog must appear even if it had no checkouts at all. Order the result by `genre`.

Tables

Example rows — the live problem includes the full dataset.

Expected output

Your answer should return 4 rows with the columns genre, Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday.

Starter code (SQL)

SELECT *
FROM Checkouts;

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