AnalystPath

Shoppers With Multiple Products in a Day

SQLMediumMid level~15 min

Problem

Table: `Scans`

```text
+-------------+---------+
| Column | Type |
+-------------+---------+
| product_id | int |
| brand_id | int |
| shopper_id | int |
| scan_day | date |
+-------------+---------+
There is no single-column primary key. Each row means shopper_id scanned the
product product_id on scan_day.
```

Find every shopper who scanned **more than one distinct product on the same
day**. Return one row per such shopper. Use the column heading `id` and sort
by `id` in ascending order.

**Example**

```text
Scans:
+------------+----------+------------+------------+
| product_id | brand_id | shopper_id | scan_day |
+------------+----------+------------+------------+
| 10 | 1 | 4 | 2024-04-01 |
| 20 | 2 | 4 | 2024-04-01 |
| 30 | 1 | 7 | 2024-04-01 |
| 30 | 1 | 7 | 2024-04-02 |
+------------+----------+------------+------------+

Output:
+----+
| id |
+----+
| 4 |
+----+
```

Shopper 4 scanned two different products (10 and 20) on 2024-04-01. Shopper 7
only ever scanned product 30, so they do not qualify.

Tables

Example rows — the live problem includes the full dataset.

Scans
product_idbrand_idshopper_idscan_day
10142024-04-01
20242024-04-01
30172024-04-01

Expected output

Your answer should return 1 row with the columns id.

Starter code (SQL)

SELECT *
FROM Scans;

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